Index: source
===================================================================
--- source	(revision 1281)
+++ source	(revision 1282)
@@ -28085,7 +28085,13 @@
 
    <li><p>Initialise <var title="">pos</var> to 0.</p></li>
 
-   <li><p>Examine <span><var title="">s</var>[<var
+   <li><p>If <span><var title="">s</var>[0]</span> is 0xEF, <span><var
+   title="">s</var>[1]</span> is 0xBB, and <span><var
+   title="">s</var>[2]</span> is 0xBF, then set <var
+   title="">pos</var> to 3. (This skips over a leading UTF-8 BOM, if
+   any.)</p></li>
+
+   <li><p><i>Loop start:</i> Examine <span><var title="">s</var>[<var
    title="">pos</var>]</span>.</p>
 
    <dl class="switch">
@@ -28119,12 +28125,12 @@
      title="">pos</var>+2</span> in <var title="">s</var> are exactly
      equal to 0x2D, 0x2D, 0x3E respectively (ASCII for "<code
      title="">--&gt;</code>"), then increase <var title="">pos</var>
-     by 3 and jump back to the previous step (step 5) in the overall
-     algorithm in this section.</li>
+     by 3 and jump back to the previous step (the step labelled
+     <i>loop start</i>) in the overall algorithm in this section.</li>
 
      <li>Otherwise, increase <var title="">pos</var> by 1.</li>
 
-     <li>Otherwise, return to step 2 in these substeps.</li>
+     <li>Return to step 2 in these substeps.</li>
 
     </ol>
 
@@ -28137,7 +28143,7 @@
     <!-- this skips past a DOCTYPE if there is one. It is brain-dead
     because we don't have to be clever to parse the Atom and RSS x.y
     DOCTYPEs, as they don't do anything clever like have internal
-    subsets of quoted ">" characters. If this fails, then that's ok,
+    subsets or quoted ">" characters. If this fails, then that's ok,
     we'll treat it as HTML which is fine since we know it's not a feed
     in that case. -->
 
@@ -28147,8 +28153,8 @@
 
      <li>If <span><var title="">s</var>[<var
      title="">pos</var>]</span> equal 0x3E, then increase <var
-     title="">pos</var> by 1 and jump back to step 5 in the overall
-     algorithm in this section.</li>
+     title="">pos</var> by 1 and jump back to the step labelled
+     <i>loop start</i> in the overall algorithm in this section.</li>
 
      <li>Otherwise, return to step 1 in these substeps.</li>
 
@@ -28167,8 +28173,9 @@
      <li>If <span><var title="">s</var>[<var
      title="">pos</var>]</span> and <span><var title="">s</var>[<var
      title="">pos</var>+1]</span> equal 0x3F and 0x3E respectively,
-     then increase <var title="">pos</var> by 1 and jump back to
-     step 5 in the overall algorithm in this section.</li>
+     then increase <var title="">pos</var> by 1 and jump back to the
+     step labelled <i>loop start</i> in the overall algorithm in this
+     section.</li>
 
      <li>Otherwise, return to step 1 in these substeps.</li>